Base | Representation |
---|---|
bin | 111111000001111100001… |
… | …110000101101001100001 |
3 | 120100002010111011001111201 |
4 | 333001330032011221201 |
5 | 1031431212220233210 |
6 | 13113453420041201 |
7 | 624635255620300 |
oct | 77017416055141 |
9 | 16302114131451 |
10 | 4331411102305 |
11 | 141aa39713a51 |
12 | 59b558993201 |
13 | 2555b14573c1 |
14 | 10d8da08c437 |
15 | 77a0b0cc53a |
hex | 3f07c385a61 |
4331411102305 has 24 divisors (see below), whose sum is σ = 6069286124352. Its totient is φ = 2958817230432.
The previous prime is 4331411102231. The next prime is 4331411102329. The reversal of 4331411102305 is 5032011141334.
4331411102305 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4331411102305 - 27 = 4331411102177 is a prime.
It is a super-2 number, since 2×43314111023052 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 33546267 + ... + 33675136.
It is an arithmetic number, because the mean of its divisors is an integer number (252886921848).
Almost surely, 24331411102305 is an apocalyptic number.
It is an amenable number.
4331411102305 is a deficient number, since it is larger than the sum of its proper divisors (1737875022047).
4331411102305 is a wasteful number, since it uses less digits than its factorization.
4331411102305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67221685 (or 67221678 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 4331411102305 its reverse (5032011141334), we get a palindrome (9363422243639).
The spelling of 4331411102305 in words is "four trillion, three hundred thirty-one billion, four hundred eleven million, one hundred two thousand, three hundred five".
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