Base | Representation |
---|---|
bin | 101000010101101110… |
… | …101001010101000001 |
3 | 11010210122100110221022 |
4 | 220111232221111001 |
5 | 1202201420104101 |
6 | 31522010035225 |
7 | 3062236546532 |
oct | 502556512501 |
9 | 133718313838 |
10 | 43314222401 |
11 | 1740782741a |
12 | 8489a18b15 |
13 | 41138a42c8 |
14 | 214c80a689 |
15 | 11d7948a1b |
hex | a15ba9541 |
43314222401 has 2 divisors, whose sum is σ = 43314222402. Its totient is φ = 43314222400.
The previous prime is 43314222379. The next prime is 43314222421. The reversal of 43314222401 is 10422241334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 43187074225 + 127148176 = 207815^2 + 11276^2 .
It is a cyclic number.
It is not a de Polignac number, because 43314222401 - 26 = 43314222337 is a prime.
It is a super-2 number, since 2×433142224012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (43314222421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21657111200 + 21657111201.
It is an arithmetic number, because the mean of its divisors is an integer number (21657111201).
Almost surely, 243314222401 is an apocalyptic number.
It is an amenable number.
43314222401 is a deficient number, since it is larger than the sum of its proper divisors (1).
43314222401 is an equidigital number, since it uses as much as digits as its factorization.
43314222401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 43314222401 its reverse (10422241334), we get a palindrome (53736463735).
The spelling of 43314222401 in words is "forty-three billion, three hundred fourteen million, two hundred twenty-two thousand, four hundred one".
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