Base | Representation |
---|---|
bin | 1100100110110010100… |
… | …10100001011100010011 |
3 | 1112102000102112122201211 |
4 | 12103121102201130103 |
5 | 24044033403203133 |
6 | 530552141240551 |
7 | 43202445205321 |
oct | 6233122413423 |
9 | 1472012478654 |
10 | 433142241043 |
11 | 157770559656 |
12 | 6bb42563157 |
13 | 31aca9cb065 |
14 | 16d6da7cd11 |
15 | b401311bcd |
hex | 64d94a1713 |
433142241043 has 2 divisors, whose sum is σ = 433142241044. Its totient is φ = 433142241042.
The previous prime is 433142241031. The next prime is 433142241079. The reversal of 433142241043 is 340142241334.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 433142241043 - 217 = 433142109971 is a prime.
It is a super-2 number, since 2×4331422410432 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 433142240996 and 433142241014.
It is not a weakly prime, because it can be changed into another prime (433142271043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216571120521 + 216571120522.
It is an arithmetic number, because the mean of its divisors is an integer number (216571120522).
Almost surely, 2433142241043 is an apocalyptic number.
433142241043 is a deficient number, since it is larger than the sum of its proper divisors (1).
433142241043 is an equidigital number, since it uses as much as digits as its factorization.
433142241043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 433142241043 its reverse (340142241334), we get a palindrome (773284482377).
The spelling of 433142241043 in words is "four hundred thirty-three billion, one hundred forty-two million, two hundred forty-one thousand, forty-three".
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