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4332142053433 is a prime number
BaseRepresentation
bin111111000010100111110…
…010011100100000111001
3120100011000102120012221201
4333002213302130200321
51031434211331202213
613114054130534201
7624662342611165
oct77024762344071
916304012505851
104332142053433
111420284283397
1259b721737361
13255699a1266c
1410d9691a1ca5
1577a503656dd
hex3f0a7c9c839

4332142053433 has 2 divisors, whose sum is σ = 4332142053434. Its totient is φ = 4332142053432.

The previous prime is 4332142053409. The next prime is 4332142053487. The reversal of 4332142053433 is 3343502412334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4128260003344 + 203882050089 = 2031812^2 + 451533^2 .

It is a cyclic number.

It is not a de Polignac number, because 4332142053433 - 29 = 4332142052921 is a prime.

It is a super-2 number, since 2×43321420534332 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4332142053392 and 4332142053401.

It is not a weakly prime, because it can be changed into another prime (4332142053233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166071026716 + 2166071026717.

It is an arithmetic number, because the mean of its divisors is an integer number (2166071026717).

Almost surely, 24332142053433 is an apocalyptic number.

It is an amenable number.

4332142053433 is a deficient number, since it is larger than the sum of its proper divisors (1).

4332142053433 is an equidigital number, since it uses as much as digits as its factorization.

4332142053433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 37.

Adding to 4332142053433 its reverse (3343502412334), we get a palindrome (7675644465767).

The spelling of 4332142053433 in words is "four trillion, three hundred thirty-two billion, one hundred forty-two million, fifty-three thousand, four hundred thirty-three".