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4332253455055 = 5866450691011
BaseRepresentation
bin111111000010101110011…
…011011010001011001111
3120100011022012012000020201
4333002232123122023033
51031434423341030210
613114113150354331
7624665164531231
oct77025633321317
916304265160221
104332253455055
111420331152049
1259b752abb9a7
132556b6b18996
1410d979cc0251
1577a5a01d53a
hex3f0ae6da2cf

4332253455055 has 4 divisors (see below), whose sum is σ = 5198704146072. Its totient is φ = 3465802764040.

The previous prime is 4332253455001. The next prime is 4332253455059. The reversal of 4332253455055 is 5505543522334.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-4332253455055 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4332253454996 and 4332253455014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4332253455059) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 433225345501 + ... + 433225345510.

It is an arithmetic number, because the mean of its divisors is an integer number (1299676036518).

Almost surely, 24332253455055 is an apocalyptic number.

4332253455055 is a deficient number, since it is larger than the sum of its proper divisors (866450691017).

4332253455055 is an equidigital number, since it uses as much as digits as its factorization.

4332253455055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 866450691016.

The product of its (nonzero) digits is 5400000, while the sum is 46.

Adding to 4332253455055 its reverse (5505543522334), we get a palindrome (9837796977389).

The spelling of 4332253455055 in words is "four trillion, three hundred thirty-two billion, two hundred fifty-three million, four hundred fifty-five thousand, fifty-five".

Divisors: 1 5 866450691011 4332253455055