Base | Representation |
---|---|
bin | 111111000010110001011… |
… | …101110001001000111111 |
3 | 120100011102202001112111202 |
4 | 333002301131301020333 |
5 | 1031440024411430210 |
6 | 13114122210410115 |
7 | 624666353563424 |
oct | 77026135611077 |
9 | 16304382045452 |
10 | 4332304405055 |
11 | 1420357991590 |
12 | 59b767b9093b |
13 | 2556c4547603 |
14 | 10d982983d4b |
15 | 77a5e7349a5 |
hex | 3f0b177123f |
4332304405055 has 16 divisors (see below), whose sum is σ = 5674778503200. Its totient is φ = 3148878956160.
The previous prime is 4332304404973. The next prime is 4332304405109. The reversal of 4332304405055 is 5505044032334.
It is a de Polignac number, because none of the positive numbers 2k-4332304405055 is a prime.
It is a super-2 number, since 2×43323044050552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23505920 + ... + 23689509.
It is an arithmetic number, because the mean of its divisors is an integer number (354673656450).
Almost surely, 24332304405055 is an apocalyptic number.
4332304405055 is a deficient number, since it is larger than the sum of its proper divisors (1342474098145).
4332304405055 is a wasteful number, since it uses less digits than its factorization.
4332304405055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47197114.
The product of its (nonzero) digits is 432000, while the sum is 38.
Adding to 4332304405055 its reverse (5505044032334), we get a palindrome (9837348437389).
The spelling of 4332304405055 in words is "four trillion, three hundred thirty-two billion, three hundred four million, four hundred five thousand, fifty-five".
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