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4332344054161 is a prime number
BaseRepresentation
bin111111000010110011110…
…101000001000110010001
3120100011112111122220212011
4333002303311001012101
51031440120034213121
613114130144302521
7625000344600454
oct77026365010621
916304474586764
104332344054161
111420378302542
1259b779311a41
132556cc81a516
1410d987d4549b
1577a62e677e1
hex3f0b3d41191

4332344054161 has 2 divisors, whose sum is σ = 4332344054162. Its totient is φ = 4332344054160.

The previous prime is 4332344054123. The next prime is 4332344054189. The reversal of 4332344054161 is 1614504432334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4196171983936 + 136172070225 = 2048456^2 + 369015^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4332344054161 is a prime.

It is not a weakly prime, because it can be changed into another prime (4332344054761) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166172027080 + 2166172027081.

It is an arithmetic number, because the mean of its divisors is an integer number (2166172027081).

Almost surely, 24332344054161 is an apocalyptic number.

It is an amenable number.

4332344054161 is a deficient number, since it is larger than the sum of its proper divisors (1).

4332344054161 is an equidigital number, since it uses as much as digits as its factorization.

4332344054161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 414720, while the sum is 40.

Adding to 4332344054161 its reverse (1614504432334), we get a palindrome (5946848486495).

The spelling of 4332344054161 in words is "four trillion, three hundred thirty-two billion, three hundred forty-four million, fifty-four thousand, one hundred sixty-one".