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4333141250089 is a prime number
BaseRepresentation
bin111111000011100011010…
…110000101000000101001
3120100020121001201200002021
4333003203112011000221
51031443233130000324
613114341223104441
7625026164625031
oct77034326050051
916306531650067
104333141250089
1114207472a8653
1259b9602a2121
132557c8a2aca2
1410da21b808c1
1577aace38ae4
hex3f0e3585029

4333141250089 has 2 divisors, whose sum is σ = 4333141250090. Its totient is φ = 4333141250088.

The previous prime is 4333141250083. The next prime is 4333141250153. The reversal of 4333141250089 is 9800521413334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2588607477225 + 1744533772864 = 1608915^2 + 1320808^2 .

It is a cyclic number.

It is not a de Polignac number, because 4333141250089 - 241 = 2134117994537 is a prime.

It is a super-2 number, since 2×43331412500892 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4333141250083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166570625044 + 2166570625045.

It is an arithmetic number, because the mean of its divisors is an integer number (2166570625045).

Almost surely, 24333141250089 is an apocalyptic number.

It is an amenable number.

4333141250089 is a deficient number, since it is larger than the sum of its proper divisors (1).

4333141250089 is an equidigital number, since it uses as much as digits as its factorization.

4333141250089 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 4333141250089 in words is "four trillion, three hundred thirty-three billion, one hundred forty-one million, two hundred fifty thousand, eighty-nine".