Base | Representation |
---|---|
bin | 111111000100011111000… |
… | …101011010010110011101 |
3 | 120100100011220122221201100 |
4 | 333010133011122112131 |
5 | 1032002311214422023 |
6 | 13115024505103313 |
7 | 625063055005215 |
oct | 77043705322635 |
9 | 16310156587640 |
10 | 4334143514013 |
11 | 1421111028345 |
12 | 59bb9ba87b39 |
13 | 25592857b771 |
14 | 10dab8d1b245 |
15 | 77b1ae15c43 |
hex | 3f11f15a59d |
4334143514013 has 24 divisors (see below), whose sum is σ = 6600111336000. Its totient is φ = 2733122888064.
The previous prime is 4334143513849. The next prime is 4334143514047. The reversal of 4334143514013 is 3104153414334.
4334143514013 is a `hidden beast` number, since 4 + 33 + 41 + 435 + 140 + 13 = 666.
It is not a de Polignac number, because 4334143514013 - 28 = 4334143513757 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4334143513013) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19476588 + ... + 19697861.
It is an arithmetic number, because the mean of its divisors is an integer number (275004639000).
Almost surely, 24334143514013 is an apocalyptic number.
It is an amenable number.
4334143514013 is a deficient number, since it is larger than the sum of its proper divisors (2265967821987).
4334143514013 is a wasteful number, since it uses less digits than its factorization.
4334143514013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39175121 (or 39175118 counting only the distinct ones).
The product of its (nonzero) digits is 103680, while the sum is 36.
Adding to 4334143514013 its reverse (3104153414334), we get a palindrome (7438296928347).
The spelling of 4334143514013 in words is "four trillion, three hundred thirty-four billion, one hundred forty-three million, five hundred fourteen thousand, thirteen".
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