Base | Representation |
---|---|
bin | 10011101101011101010011… |
… | …10001101000111011011011 |
3 | 12200110120210111220112112201 |
4 | 21312232221301220323123 |
5 | 21140114202004034024 |
6 | 232103355523551031 |
7 | 12062311643431033 |
oct | 1166565161507333 |
9 | 180416714815481 |
10 | 43343363346139 |
11 | 128a08a971689a |
12 | 4a4029882b477 |
13 | 1b25352a39b5c |
14 | a9bb8966a8c3 |
15 | 5026d8a1d744 |
hex | 276ba9c68edb |
43343363346139 has 2 divisors, whose sum is σ = 43343363346140. Its totient is φ = 43343363346138.
The previous prime is 43343363346097. The next prime is 43343363346193. The reversal of 43343363346139 is 93164336334334.
Together with next prime (43343363346193) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43343363346139 - 27 = 43343363346011 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 43343363346139.
It is not a weakly prime, because it can be changed into another prime (43343363347139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21671681673069 + 21671681673070.
It is an arithmetic number, because the mean of its divisors is an integer number (21671681673070).
Almost surely, 243343363346139 is an apocalyptic number.
43343363346139 is a deficient number, since it is larger than the sum of its proper divisors (1).
43343363346139 is an equidigital number, since it uses as much as digits as its factorization.
43343363346139 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 45349632, while the sum is 55.
The spelling of 43343363346139 in words is "forty-three trillion, three hundred forty-three billion, three hundred sixty-three million, three hundred forty-six thousand, one hundred thirty-nine".
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