Base | Representation |
---|---|
bin | 101000010111011110… |
… | …111000000110001011 |
3 | 11010212200201012102211 |
4 | 220113132320012023 |
5 | 1202231433034034 |
6 | 31524540405551 |
7 | 3063044613115 |
oct | 502736700613 |
9 | 133780635384 |
10 | 43343643019 |
11 | 174223a1586 |
12 | 84978468b7 |
13 | 4119a05661 |
14 | 21526a83b5 |
15 | 11da30ad64 |
hex | a177b818b |
43343643019 has 2 divisors, whose sum is σ = 43343643020. Its totient is φ = 43343643018.
The previous prime is 43343643001. The next prime is 43343643029. The reversal of 43343643019 is 91034634334.
43343643019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43343643019 - 213 = 43343634827 is a prime.
It is a super-2 number, since 2×433436430192 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (43343643029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21671821509 + 21671821510.
It is an arithmetic number, because the mean of its divisors is an integer number (21671821510).
Almost surely, 243343643019 is an apocalyptic number.
43343643019 is a deficient number, since it is larger than the sum of its proper divisors (1).
43343643019 is an equidigital number, since it uses as much as digits as its factorization.
43343643019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 279936, while the sum is 40.
The spelling of 43343643019 in words is "forty-three billion, three hundred forty-three million, six hundred forty-three thousand, nineteen".
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