Search a number
-
+
4334405313401 is a prime number
BaseRepresentation
bin111111000100101110101…
…100000110001101111001
3120100100212011021201221222
4333010232230012031321
51032003330230012101
613115110500241425
7625102414162562
oct77045654061571
916310764251858
104334405313401
111421235890079
125a00536a0275
1325596a892a47
1410db019c9169
1577b33dcb01b
hex3f12eb06379

4334405313401 has 2 divisors, whose sum is σ = 4334405313402. Its totient is φ = 4334405313400.

The previous prime is 4334405313353. The next prime is 4334405313439. The reversal of 4334405313401 is 1043135044334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3927075439225 + 407329874176 = 1981685^2 + 638224^2 .

It is a cyclic number.

It is not a de Polignac number, because 4334405313401 - 214 = 4334405297017 is a prime.

It is not a weakly prime, because it can be changed into another prime (4334405913401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2167202656700 + 2167202656701.

It is an arithmetic number, because the mean of its divisors is an integer number (2167202656701).

Almost surely, 24334405313401 is an apocalyptic number.

It is an amenable number.

4334405313401 is a deficient number, since it is larger than the sum of its proper divisors (1).

4334405313401 is an equidigital number, since it uses as much as digits as its factorization.

4334405313401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 35.

The spelling of 4334405313401 in words is "four trillion, three hundred thirty-four billion, four hundred five million, three hundred thirteen thousand, four hundred one".