Base | Representation |
---|---|
bin | 10011101101011111010100… |
… | …01100001011010001110001 |
3 | 12200110200120211102200212021 |
4 | 21312233222030023101301 |
5 | 21140123410133410101 |
6 | 232104055051031441 |
7 | 12062350505263603 |
oct | 1166575214132161 |
9 | 180420524380767 |
10 | 43344444044401 |
11 | 128a1303748455 |
12 | 4a4053a73b581 |
13 | 1b254958c0196 |
14 | a9bc4cdc3173 |
15 | 50274d8405a1 |
hex | 276bea30b471 |
43344444044401 has 2 divisors, whose sum is σ = 43344444044402. Its totient is φ = 43344444044400.
The previous prime is 43344444044371. The next prime is 43344444044413. The reversal of 43344444044401 is 10444044444334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28389022578225 + 14955421466176 = 5328135^2 + 3867224^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43344444044401 is a prime.
It is not a weakly prime, because it can be changed into another prime (43344444084401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21672222022200 + 21672222022201.
It is an arithmetic number, because the mean of its divisors is an integer number (21672222022201).
Almost surely, 243344444044401 is an apocalyptic number.
It is an amenable number.
43344444044401 is a deficient number, since it is larger than the sum of its proper divisors (1).
43344444044401 is an equidigital number, since it uses as much as digits as its factorization.
43344444044401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2359296, while the sum is 43.
Adding to 43344444044401 its reverse (10444044444334), we get a palindrome (53788488488735).
The spelling of 43344444044401 in words is "forty-three trillion, three hundred forty-four billion, four hundred forty-four million, forty-four thousand, four hundred one".
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