Base | Representation |
---|---|
bin | 101000010111111110… |
… | …111011001101001001 |
3 | 11010220021112000220122 |
4 | 220113332323031021 |
5 | 1202241110404421 |
6 | 31525440433025 |
7 | 3063206203613 |
oct | 502776731511 |
9 | 133807460818 |
10 | 43352044361 |
11 | 1742710a63a |
12 | 849a618775 |
13 | 411b687672 |
14 | 2153853db3 |
15 | 11dae1a2ab |
hex | a17fbb349 |
43352044361 has 2 divisors, whose sum is σ = 43352044362. Its totient is φ = 43352044360.
The previous prime is 43352044327. The next prime is 43352044399. The reversal of 43352044361 is 16344025334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42207237136 + 1144807225 = 205444^2 + 33835^2 .
It is a cyclic number.
It is not a de Polignac number, because 43352044361 - 210 = 43352043337 is a prime.
It is a super-2 number, since 2×433520443612 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (43352044961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21676022180 + 21676022181.
It is an arithmetic number, because the mean of its divisors is an integer number (21676022181).
Almost surely, 243352044361 is an apocalyptic number.
It is an amenable number.
43352044361 is a deficient number, since it is larger than the sum of its proper divisors (1).
43352044361 is an equidigital number, since it uses as much as digits as its factorization.
43352044361 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 43352044361 its reverse (16344025334), we get a palindrome (59696069695).
The spelling of 43352044361 in words is "forty-three billion, three hundred fifty-two million, forty-four thousand, three hundred sixty-one".
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