Base | Representation |
---|---|
bin | 101000011000011110… |
… | …111000110111000001 |
3 | 11010220212021201201222 |
4 | 220120132320313001 |
5 | 1202300232021421 |
6 | 31530340204425 |
7 | 3063340342313 |
oct | 503036706701 |
9 | 133825251658 |
10 | 43360423361 |
11 | 17430912932 |
12 | 84a1399715 |
13 | 412032c458 |
14 | 21549d57b3 |
15 | 11dba22cab |
hex | a187b8dc1 |
43360423361 has 2 divisors, whose sum is σ = 43360423362. Its totient is φ = 43360423360.
The previous prime is 43360423339. The next prime is 43360423367. The reversal of 43360423361 is 16332406334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 41626200625 + 1734222736 = 204025^2 + 41644^2 .
It is a cyclic number.
It is not a de Polignac number, because 43360423361 - 210 = 43360422337 is a prime.
It is not a weakly prime, because it can be changed into another prime (43360423367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21680211680 + 21680211681.
It is an arithmetic number, because the mean of its divisors is an integer number (21680211681).
Almost surely, 243360423361 is an apocalyptic number.
It is an amenable number.
43360423361 is a deficient number, since it is larger than the sum of its proper divisors (1).
43360423361 is an equidigital number, since it uses as much as digits as its factorization.
43360423361 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 35.
Adding to 43360423361 its reverse (16332406334), we get a palindrome (59692829695).
The spelling of 43360423361 in words is "forty-three billion, three hundred sixty million, four hundred twenty-three thousand, three hundred sixty-one".
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