Base | Representation |
---|---|
bin | 111111001001111101000… |
… | …000110011010111000011 |
3 | 120100220100001122101001210 |
4 | 333021331000303113003 |
5 | 1032101322132100311 |
6 | 13121435225101203 |
7 | 625361413065540 |
oct | 77117500632703 |
9 | 16326301571053 |
10 | 4340014331331 |
11 | 1423653a45288 |
12 | 5a115a027803 |
13 | 256352956a73 |
14 | 1100b48ddbc7 |
15 | 77d615323a6 |
hex | 3f27d0335c3 |
4340014331331 has 32 divisors (see below), whose sum is σ = 6842240204800. Its totient is φ = 2394540779040.
The previous prime is 4340014331201. The next prime is 4340014331333. The reversal of 4340014331331 is 1331334100434.
It is not a de Polignac number, because 4340014331331 - 229 = 4339477460419 is a prime.
It is a super-2 number, since 2×43400143313312 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4340014331333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7307251 + ... + 7878828.
It is an arithmetic number, because the mean of its divisors is an integer number (213820006400).
Almost surely, 24340014331331 is an apocalyptic number.
4340014331331 is a deficient number, since it is larger than the sum of its proper divisors (2502225873469).
4340014331331 is a wasteful number, since it uses less digits than its factorization.
4340014331331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15186559.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 4340014331331 its reverse (1331334100434), we get a palindrome (5671348431765).
The spelling of 4340014331331 in words is "four trillion, three hundred forty billion, fourteen million, three hundred thirty-one thousand, three hundred thirty-one".
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