4340102131 has 2 divisors, whose sum is σ = 4340102132. Its totient is φ = 4340102130.

The previous prime is 4340102089. The next prime is 4340102147. The reversal of 4340102131 is 1312010434.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4340102131 - 2⁷ = 4340102003 is a prime.

It is a super-2 number, since 2×4340102131² = 37672973015021482322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4340102099 and 4340102108.

It is not a weakly prime, because it can be changed into another prime (4340102161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170051065 + 2170051066.

It is an arithmetic number, because the mean of its divisors is an integer number (2170051066).

Almost surely, 2^4340102131 is an apocalyptic number.

4340102131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4340102131 is an equidigital number, since it uses as much as digits as its factorization.

4340102131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 4340102131 is about 65879.4515080385. The cubic root of 4340102131 is about 1631.1728459058.

Adding to 4340102131 its reverse (1312010434), we get a palindrome (5652112565).

The spelling of 4340102131 in words is "four billion, three hundred forty million, one hundred two thousand, one hundred thirty-one".