Base | Representation |
---|---|
bin | 111111001010000011111… |
… | …110010111001111101010 |
3 | 120100220122012102111000002 |
4 | 333022003332113033222 |
5 | 1032102042032214034 |
6 | 13121455000343002 |
7 | 625364331634451 |
oct | 77120376271752 |
9 | 16326565374002 |
10 | 4340131132394 |
11 | 1423703971692 |
12 | 5a1191174a62 |
13 | 256370c00915 |
14 | 1100c6225b98 |
15 | 77d6b904e7e |
hex | 3f283f973ea |
4340131132394 has 4 divisors (see below), whose sum is σ = 6510196698594. Its totient is φ = 2170065566196.
The previous prime is 4340131132373. The next prime is 4340131132411. The reversal of 4340131132394 is 4932311310434.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 4183681614025 + 156449518369 = 2045405^2 + 395537^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1085032783097 + ... + 1085032783100.
Almost surely, 24340131132394 is an apocalyptic number.
4340131132394 is a deficient number, since it is larger than the sum of its proper divisors (2170065566200).
4340131132394 is a wasteful number, since it uses less digits than its factorization.
4340131132394 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2170065566199.
The product of its (nonzero) digits is 93312, while the sum is 38.
The spelling of 4340131132394 in words is "four trillion, three hundred forty billion, one hundred thirty-one million, one hundred thirty-two thousand, three hundred ninety-four".
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