Base | Representation |
---|---|
bin | 111111001010001000000… |
… | …101100101001010111111 |
3 | 120100220211000021002110121 |
4 | 333022020011211022333 |
5 | 1032102212213231221 |
6 | 13121505503315411 |
7 | 625366130300350 |
oct | 77121005451277 |
9 | 16326730232417 |
10 | 4340200133311 |
11 | 1423739910039 |
12 | 5a11b02abb67 |
13 | 2563822ac773 |
14 | 1100d1467d27 |
15 | 77d729d4a41 |
hex | 3f2881652bf |
4340200133311 has 8 divisors (see below), whose sum is σ = 4960242381344. Its totient is φ = 3720161299680.
The previous prime is 4340200133263. The next prime is 4340200133351. The reversal of 4340200133311 is 1133310020434.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4340200133311 - 29 = 4340200132799 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4340200133351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3076801 + ... + 4259941.
It is an arithmetic number, because the mean of its divisors is an integer number (620030297668).
Almost surely, 24340200133311 is an apocalyptic number.
4340200133311 is a deficient number, since it is larger than the sum of its proper divisors (620042248033).
4340200133311 is a wasteful number, since it uses less digits than its factorization.
4340200133311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1707201.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 4340200133311 its reverse (1133310020434), we get a palindrome (5473510153745).
The spelling of 4340200133311 in words is "four trillion, three hundred forty billion, two hundred million, one hundred thirty-three thousand, three hundred eleven".
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