Base | Representation |
---|---|
bin | 111111001010001000111… |
… | …010100001110100011011 |
3 | 120100220211222101021002222 |
4 | 333022020322201310123 |
5 | 1032102224241410321 |
6 | 13121511121014255 |
7 | 625366356256466 |
oct | 77121072416433 |
9 | 16326758337088 |
10 | 4340214013211 |
11 | 142374673022a |
12 | 5a11b4a8438b |
13 | 25638512c31b |
14 | 1100d323c2dd |
15 | 77d73d273ab |
hex | 3f288ea1d1b |
4340214013211 has 16 divisors (see below), whose sum is σ = 4526198617248. Its totient is φ = 4158711398400.
The previous prime is 4340214013199. The next prime is 4340214013283. The reversal of 4340214013211 is 1123104120434.
It is a cyclic number.
It is not a de Polignac number, because 4340214013211 - 210 = 4340214012187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4340214016211) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3644390 + ... + 4686363.
It is an arithmetic number, because the mean of its divisors is an integer number (282887413578).
Almost surely, 24340214013211 is an apocalyptic number.
4340214013211 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
4340214013211 is a deficient number, since it is larger than the sum of its proper divisors (185984604037).
4340214013211 is a wasteful number, since it uses less digits than its factorization.
4340214013211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8331022.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 4340214013211 its reverse (1123104120434), we get a palindrome (5463318133645).
The spelling of 4340214013211 in words is "four trillion, three hundred forty billion, two hundred fourteen million, thirteen thousand, two hundred eleven".
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