Base | Representation |
---|---|
bin | 110001010101111100011010… |
… | …0011101010110111100111011 |
3 | 2002220202100010000120211011112 |
4 | 1202223320310131112330323 |
5 | 423342024141320211103 |
6 | 4135032034412350535 |
7 | 160264143563422316 |
oct | 14253706435267473 |
9 | 2086670100524145 |
10 | 434024505241403 |
11 | 11632583923893a |
12 | 40818a3477544b |
13 | 1582444865076b |
14 | 7926c806cb97d |
15 | 3529e90404cd8 |
hex | 18abe34756f3b |
434024505241403 has 2 divisors, whose sum is σ = 434024505241404. Its totient is φ = 434024505241402.
The previous prime is 434024505241351. The next prime is 434024505241441. The reversal of 434024505241403 is 304142505420434.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 434024505241403 - 26 = 434024505241339 is a prime.
It is not a weakly prime, because it can be changed into another prime (434024505241303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217012252620701 + 217012252620702.
It is an arithmetic number, because the mean of its divisors is an integer number (217012252620702).
Almost surely, 2434024505241403 is an apocalyptic number.
434024505241403 is a deficient number, since it is larger than the sum of its proper divisors (1).
434024505241403 is an equidigital number, since it uses as much as digits as its factorization.
434024505241403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 921600, while the sum is 41.
The spelling of 434024505241403 in words is "four hundred thirty-four trillion, twenty-four billion, five hundred five million, two hundred forty-one thousand, four hundred three".
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