Base | Representation |
---|---|
bin | 111111001010010100110… |
… | …101011101111101110111 |
3 | 120100221100220201022122210 |
4 | 333022110311131331313 |
5 | 1032103131441411203 |
6 | 13121543023424503 |
7 | 625404335244234 |
oct | 77122465357567 |
9 | 16327326638583 |
10 | 4340414013303 |
11 | 1423839613265 |
12 | 5a124ba55133 |
13 | 2563b76b6684 |
14 | 110111a2078b |
15 | 77d86681803 |
hex | 3f294d5df77 |
4340414013303 has 4 divisors (see below), whose sum is σ = 5787218684408. Its totient is φ = 2893609342200.
The previous prime is 4340414013289. The next prime is 4340414013389. The reversal of 4340414013303 is 3033104140434.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 4340414013303 - 212 = 4340414009207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4340414013203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723402335548 + ... + 723402335553.
It is an arithmetic number, because the mean of its divisors is an integer number (1446804671102).
Almost surely, 24340414013303 is an apocalyptic number.
4340414013303 is a deficient number, since it is larger than the sum of its proper divisors (1446804671105).
4340414013303 is a wasteful number, since it uses less digits than its factorization.
4340414013303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1446804671104.
The product of its (nonzero) digits is 20736, while the sum is 30.
Adding to 4340414013303 its reverse (3033104140434), we get a palindrome (7373518153737).
The spelling of 4340414013303 in words is "four trillion, three hundred forty billion, four hundred fourteen million, thirteen thousand, three hundred three".
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