Base | Representation |
---|---|
bin | 111111001010010110011… |
… | …100111100101110001111 |
3 | 120100221102210202111122101 |
4 | 333022112130330232033 |
5 | 1032103210412440421 |
6 | 13121545433055531 |
7 | 625405114645156 |
oct | 77122634745617 |
9 | 16327383674571 |
10 | 4340441140111 |
11 | 142385296100a |
12 | 5a1258b575a7 |
13 | 2563c01c393b |
14 | 11011548259d |
15 | 77d88c3e191 |
hex | 3f29673cb8f |
4340441140111 has 4 divisors (see below), whose sum is σ = 4457750360152. Its totient is φ = 4223131920072.
The previous prime is 4340441140099. The next prime is 4340441140159. The reversal of 4340441140111 is 1110411440434.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4340441140111 - 217 = 4340441009039 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 4340441140111.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4340441147111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58654609965 + ... + 58654610038.
It is an arithmetic number, because the mean of its divisors is an integer number (1114437590038).
Almost surely, 24340441140111 is an apocalyptic number.
4340441140111 is a deficient number, since it is larger than the sum of its proper divisors (117309220041).
4340441140111 is a wasteful number, since it uses less digits than its factorization.
4340441140111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117309220040.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 4340441140111 its reverse (1110411440434), we get a palindrome (5450852580545).
The spelling of 4340441140111 in words is "four trillion, three hundred forty billion, four hundred forty-one million, one hundred forty thousand, one hundred eleven".
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