Base | Representation |
---|---|
bin | 111111001010111101111… |
… | …011011110010000010001 |
3 | 120101000010222000111101211 |
4 | 333022331323132100101 |
5 | 1032111034441000301 |
6 | 13122135252500121 |
7 | 625430406344134 |
oct | 77127573362021 |
9 | 16330128014354 |
10 | 4341103453201 |
11 | 14240627aa6a9 |
12 | 5a140291a641 |
13 | 256497499288 |
14 | 11017940a21b |
15 | 77dc6e6a051 |
hex | 3f2bdede411 |
4341103453201 has 2 divisors, whose sum is σ = 4341103453202. Its totient is φ = 4341103453200.
The previous prime is 4341103453187. The next prime is 4341103453243. The reversal of 4341103453201 is 1023543011434.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3749834729601 + 591268723600 = 1936449^2 + 768940^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4341103453201 is a prime.
It is not a weakly prime, because it can be changed into another prime (4341103459201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170551726600 + 2170551726601.
It is an arithmetic number, because the mean of its divisors is an integer number (2170551726601).
Almost surely, 24341103453201 is an apocalyptic number.
It is an amenable number.
4341103453201 is a deficient number, since it is larger than the sum of its proper divisors (1).
4341103453201 is an equidigital number, since it uses as much as digits as its factorization.
4341103453201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 4341103453201 its reverse (1023543011434), we get a palindrome (5364646464635).
The spelling of 4341103453201 in words is "four trillion, three hundred forty-one billion, one hundred three million, four hundred fifty-three thousand, two hundred one".
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