Search a number
-
+
43411040034137 is a prime number
BaseRepresentation
bin10011101111011011010111…
…00111101101110101011001
312200201001111000112111111122
421313231223213231311121
521142221302222043022
6232154431222135025
712100226016664226
oct1167555347556531
9180631430474448
1043411040034137
11129175784151a6
124a51425581475
131b2b849a39579
14aa11698a694d
1550434a1a5742
hex277b6b9edd59

43411040034137 has 2 divisors, whose sum is σ = 43411040034138. Its totient is φ = 43411040034136.

The previous prime is 43411040034017. The next prime is 43411040034151. The reversal of 43411040034137 is 73143004011434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43392112878361 + 18927155776 = 6587269^2 + 137576^2 .

It is a cyclic number.

It is not a de Polignac number, because 43411040034137 - 210 = 43411040033113 is a prime.

It is a super-2 number, since 2×434110400341372 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43411040034097 and 43411040034106.

It is not a weakly prime, because it can be changed into another prime (43411040034737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21705520017068 + 21705520017069.

It is an arithmetic number, because the mean of its divisors is an integer number (21705520017069).

Almost surely, 243411040034137 is an apocalyptic number.

It is an amenable number.

43411040034137 is a deficient number, since it is larger than the sum of its proper divisors (1).

43411040034137 is an equidigital number, since it uses as much as digits as its factorization.

43411040034137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 35.

The spelling of 43411040034137 in words is "forty-three trillion, four hundred eleven billion, forty million, thirty-four thousand, one hundred thirty-seven".