Base | Representation |
---|---|
bin | 1100101000100111001… |
… | …10010010001101010011 |
3 | 1112111112121022100210221 |
4 | 12110103212102031103 |
5 | 24103034322000201 |
6 | 531233204533511 |
7 | 43235624236360 |
oct | 6242346221523 |
9 | 1474477270727 |
10 | 434120500051 |
11 | 158122783077 |
12 | 701760b1297 |
13 | 31c25595544 |
14 | 1702396b467 |
15 | b45c14b4a1 |
hex | 6513992353 |
434120500051 has 12 divisors (see below), whose sum is σ = 527039027728. Its totient is φ = 350214855552.
The previous prime is 434120499991. The next prime is 434120500091. The reversal of 434120500051 is 150005021434.
It is a happy number.
It is not a de Polignac number, because 434120500051 - 213 = 434120491859 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 434120499989 and 434120500025.
It is not an unprimeable number, because it can be changed into a prime (434120500091) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 107294196 + ... + 107298241.
Almost surely, 2434120500051 is an apocalyptic number.
434120500051 is a deficient number, since it is larger than the sum of its proper divisors (92918527677).
434120500051 is a wasteful number, since it uses less digits than its factorization.
434120500051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 214592478 (or 214592461 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 434120500051 its reverse (150005021434), we get a palindrome (584125521485).
The spelling of 434120500051 in words is "four hundred thirty-four billion, one hundred twenty million, five hundred thousand, fifty-one".
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