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4341241215103 = 131553215030027
BaseRepresentation
bin111111001011000110001…
…000111111100001111111
3120101000111120020112012111
4333023012020333201333
51032111330222340403
613122201053314451
7625434001323262
oct77130610774177
916330446215174
104341241215103
111424123543211
125a1440a95a27
132564b9ba19b0
1411018d82acd9
1577dd40cd56d
hex3f2c623f87f

4341241215103 has 8 divisors (see below), whose sum is σ = 4678193289168. Its totient is φ = 4004719204224.

The previous prime is 4341241215029. The next prime is 4341241215119. The reversal of 4341241215103 is 3015121421434.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4341241215103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4341241215133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 107494825 + ... + 107535202.

It is an arithmetic number, because the mean of its divisors is an integer number (584774161146).

Almost surely, 24341241215103 is an apocalyptic number.

4341241215103 is a deficient number, since it is larger than the sum of its proper divisors (336952074065).

4341241215103 is a wasteful number, since it uses less digits than its factorization.

4341241215103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215031593.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 4341241215103 its reverse (3015121421434), we get a palindrome (7356362636537).

The spelling of 4341241215103 in words is "four trillion, three hundred forty-one billion, two hundred forty-one million, two hundred fifteen thousand, one hundred three".

Divisors: 1 13 1553 20189 215030027 2795390351 333941631931 4341241215103