Base | Representation |
---|---|
bin | 1100101000100111101… |
… | …01001101010011011001 |
3 | 1112111112212200010011102 |
4 | 12110103311031103121 |
5 | 24103041322141441 |
6 | 531233424441145 |
7 | 43236002422001 |
oct | 6242365152331 |
9 | 1474485603142 |
10 | 434124412121 |
11 | 158124a05294 |
12 | 701774791b5 |
13 | 31c2633508a |
14 | 170242a9001 |
15 | b45c67069b |
hex | 6513d4d4d9 |
434124412121 has 2 divisors, whose sum is σ = 434124412122. Its totient is φ = 434124412120.
The previous prime is 434124412067. The next prime is 434124412133. The reversal of 434124412121 is 121214421434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 402158905600 + 31965506521 = 634160^2 + 178789^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-434124412121 is a prime.
It is not a weakly prime, because it can be changed into another prime (434124412151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217062206060 + 217062206061.
It is an arithmetic number, because the mean of its divisors is an integer number (217062206061).
Almost surely, 2434124412121 is an apocalyptic number.
It is an amenable number.
434124412121 is a deficient number, since it is larger than the sum of its proper divisors (1).
434124412121 is an equidigital number, since it uses as much as digits as its factorization.
434124412121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6144, while the sum is 29.
Adding to 434124412121 its reverse (121214421434), we get a palindrome (555338833555).
The spelling of 434124412121 in words is "four hundred thirty-four billion, one hundred twenty-four million, four hundred twelve thousand, one hundred twenty-one".
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