Base | Representation |
---|---|
bin | 111111001011001010011… |
… | …100011001101110111011 |
3 | 120101000200121002111202122 |
4 | 333023022130121232323 |
5 | 1032112002213141102 |
6 | 13122212152551455 |
7 | 625435536100034 |
oct | 77131234315673 |
9 | 16330617074678 |
10 | 4341313412027 |
11 | 1424160274899 |
12 | 5a14610b258b |
13 | 2564cbb2c477 |
14 | 110199261a8b |
15 | 77dda5e00a2 |
hex | 3f2ca719bbb |
4341313412027 has 2 divisors, whose sum is σ = 4341313412028. Its totient is φ = 4341313412026.
The previous prime is 4341313411879. The next prime is 4341313412083. The reversal of 4341313412027 is 7202143131434.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4341313412027 - 210 = 4341313411003 is a prime.
It is not a weakly prime, because it can be changed into another prime (4341313412327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170656706013 + 2170656706014.
It is an arithmetic number, because the mean of its divisors is an integer number (2170656706014).
Almost surely, 24341313412027 is an apocalyptic number.
4341313412027 is a deficient number, since it is larger than the sum of its proper divisors (1).
4341313412027 is an equidigital number, since it uses as much as digits as its factorization.
4341313412027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
The spelling of 4341313412027 in words is "four trillion, three hundred forty-one billion, three hundred thirteen million, four hundred twelve thousand, twenty-seven".
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