Base | Representation |
---|---|
bin | 111111001011001100101… |
… | …100010011011100011001 |
3 | 120101000210020002000221211 |
4 | 333023030230103130121 |
5 | 1032112041342310001 |
6 | 13122220021303121 |
7 | 625436504532406 |
oct | 77131454233431 |
9 | 16330706060854 |
10 | 4341351135001 |
11 | 142417a59a701 |
12 | 5a1471864aa1 |
13 | 2565068a975a |
14 | 1101a02812ad |
15 | 77ddda92351 |
hex | 3f2ccb13719 |
4341351135001 has 2 divisors, whose sum is σ = 4341351135002. Its totient is φ = 4341351135000.
The previous prime is 4341351134977. The next prime is 4341351135041. The reversal of 4341351135001 is 1005311531434.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3860930255625 + 480420879376 = 1964925^2 + 693124^2 .
It is a cyclic number.
It is not a de Polignac number, because 4341351135001 - 29 = 4341351134489 is a prime.
It is not a weakly prime, because it can be changed into another prime (4341351135041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170675567500 + 2170675567501.
It is an arithmetic number, because the mean of its divisors is an integer number (2170675567501).
Almost surely, 24341351135001 is an apocalyptic number.
It is an amenable number.
4341351135001 is a deficient number, since it is larger than the sum of its proper divisors (1).
4341351135001 is an equidigital number, since it uses as much as digits as its factorization.
4341351135001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 4341351135001 its reverse (1005311531434), we get a palindrome (5346662666435).
The spelling of 4341351135001 in words is "four trillion, three hundred forty-one billion, three hundred fifty-one million, one hundred thirty-five thousand, one".
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