Base | Representation |
---|---|
bin | 111111001011001111110… |
… | …000011100001110101101 |
3 | 120101000220210211020201222 |
4 | 333023033300130032231 |
5 | 1032112143023114323 |
6 | 13122225055313125 |
7 | 625441000546040 |
oct | 77131760341655 |
9 | 16330823736658 |
10 | 4341402551213 |
11 | 14241a6618442 |
12 | 5a1486b1b7a5 |
13 | 25651443c650 |
14 | 1101a7026c57 |
15 | 77de334b9c8 |
hex | 3f2cfc1c3ad |
4341402551213 has 32 divisors (see below), whose sum is σ = 5355558899712. Its totient is φ = 3427061400000.
The previous prime is 4341402551191. The next prime is 4341402551231. The reversal of 4341402551213 is 3121552041434.
It is not a de Polignac number, because 4341402551213 - 26 = 4341402551149 is a prime.
It is a super-2 number, since 2×43414025512132 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4341402551243) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 71796170 + ... + 71856612.
It is an arithmetic number, because the mean of its divisors is an integer number (167361215616).
Almost surely, 24341402551213 is an apocalyptic number.
It is an amenable number.
4341402551213 is a deficient number, since it is larger than the sum of its proper divisors (1014156348499).
4341402551213 is a wasteful number, since it uses less digits than its factorization.
4341402551213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62265.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 4341402551213 its reverse (3121552041434), we get a palindrome (7462954592647).
The spelling of 4341402551213 in words is "four trillion, three hundred forty-one billion, four hundred two million, five hundred fifty-one thousand, two hundred thirteen".
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