Base | Representation |
---|---|
bin | 1100101000110000110… |
… | …10101000110110001011 |
3 | 1112111202020102002221201 |
4 | 12110120122220312023 |
5 | 24103221020130011 |
6 | 531245213245031 |
7 | 43240625302336 |
oct | 6243032506613 |
9 | 1474666362851 |
10 | 434201333131 |
11 | 158164373175 |
12 | 70199193777 |
13 | 31c39257b77 |
14 | 170305ad61d |
15 | b4642b6cc1 |
hex | 65186a8d8b |
434201333131 has 2 divisors, whose sum is σ = 434201333132. Its totient is φ = 434201333130.
The previous prime is 434201333089. The next prime is 434201333191. The reversal of 434201333131 is 131333102434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 434201333131 - 29 = 434201332619 is a prime.
It is a super-2 number, since 2×4342013331312 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 434201333131.
It is not a weakly prime, because it can be changed into another prime (434201333191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217100666565 + 217100666566.
It is an arithmetic number, because the mean of its divisors is an integer number (217100666566).
Almost surely, 2434201333131 is an apocalyptic number.
434201333131 is a deficient number, since it is larger than the sum of its proper divisors (1).
434201333131 is an equidigital number, since it uses as much as digits as its factorization.
434201333131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 434201333131 its reverse (131333102434), we get a palindrome (565534435565).
The spelling of 434201333131 in words is "four hundred thirty-four billion, two hundred one million, three hundred thirty-three thousand, one hundred thirty-one".
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