Base | Representation |
---|---|
bin | 111111001011110101111… |
… | …100110101010111100001 |
3 | 120101002120110120101121222 |
4 | 333023311330311113201 |
5 | 1032120001043142423 |
6 | 13122412425424425 |
7 | 625462611243542 |
oct | 77136574652741 |
9 | 16332513511558 |
10 | 4342043334113 |
11 | 14244a52a1091 |
12 | 5a162563b115 |
13 | 2565b7117224 |
14 | 1102281884c9 |
15 | 77e2e7233c8 |
hex | 3f2f5f355e1 |
4342043334113 has 2 divisors, whose sum is σ = 4342043334114. Its totient is φ = 4342043334112.
The previous prime is 4342043334059. The next prime is 4342043334143. The reversal of 4342043334113 is 3114333402434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3200889544609 + 1141153789504 = 1789103^2 + 1068248^2 .
It is a cyclic number.
It is not a de Polignac number, because 4342043334113 - 26 = 4342043334049 is a prime.
It is not a weakly prime, because it can be changed into another prime (4342043334143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2171021667056 + 2171021667057.
It is an arithmetic number, because the mean of its divisors is an integer number (2171021667057).
Almost surely, 24342043334113 is an apocalyptic number.
It is an amenable number.
4342043334113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4342043334113 is an equidigital number, since it uses as much as digits as its factorization.
4342043334113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 4342043334113 its reverse (3114333402434), we get a palindrome (7456376736547).
The spelling of 4342043334113 in words is "four trillion, three hundred forty-two billion, forty-three million, three hundred thirty-four thousand, one hundred thirteen".
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