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4342102012435 = 511194155121543
BaseRepresentation
bin111111001011111001011…
…100101011001000010011
3120101002201112222120011011
4333023321130223020103
51032120111103344220
613122422323231351
7625464223064425
oct77137134531023
916332645876134
104342102012435
111424525429a70
125a1641218557
132565c6320725
14110231ca0815
1577e3496465a
hex3f2f972b213

4342102012435 has 16 divisors (see below), whose sum is σ = 5983375023360. Its totient is φ = 2991687510240.

The previous prime is 4342102012393. The next prime is 4342102012471. The reversal of 4342102012435 is 5342102012434.

It is not a de Polignac number, because 4342102012435 - 213 = 4342102004243 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4342102012397 and 4342102012406.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2077559727 + ... + 2077561816.

It is an arithmetic number, because the mean of its divisors is an integer number (373960938960).

Almost surely, 24342102012435 is an apocalyptic number.

4342102012435 is a deficient number, since it is larger than the sum of its proper divisors (1641273010925).

4342102012435 is a wasteful number, since it uses less digits than its factorization.

4342102012435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4155121578.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 4342102012435 its reverse (5342102012434), we get a palindrome (9684204024869).

Subtracting 4342102012435 from its reverse (5342102012434), we obtain a palindrome (999999999999).

The spelling of 4342102012435 in words is "four trillion, three hundred forty-two billion, one hundred two million, twelve thousand, four hundred thirty-five".

Divisors: 1 5 11 19 55 95 209 1045 4155121543 20775607715 45706336973 78947309317 228531684865 394736546585 868420402487 4342102012435