Base | Representation |
---|---|
bin | 1100101000110010001… |
… | …11101001000000111101 |
3 | 1112111210001121110121221 |
4 | 12110121013221000331 |
5 | 24103232030132201 |
6 | 531250314153341 |
7 | 43241130465406 |
oct | 6243107510075 |
9 | 1474701543557 |
10 | 434213130301 |
11 | 15816aaa05a5 |
12 | 701a1122851 |
13 | 31c3b828742 |
14 | 17031da09ad |
15 | b4653474a1 |
hex | 65191e903d |
434213130301 has 4 divisors (see below), whose sum is σ = 448220005504. Its totient is φ = 420206255100.
The previous prime is 434213130287. The next prime is 434213130311. The reversal of 434213130301 is 103031312434.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 434213130301 - 27 = 434213130173 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (434213130311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7003437555 + ... + 7003437616.
It is an arithmetic number, because the mean of its divisors is an integer number (112055001376).
Almost surely, 2434213130301 is an apocalyptic number.
It is an amenable number.
434213130301 is a deficient number, since it is larger than the sum of its proper divisors (14006875203).
434213130301 is a wasteful number, since it uses less digits than its factorization.
434213130301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14006875202.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 434213130301 its reverse (103031312434), we get a palindrome (537244442735).
The spelling of 434213130301 in words is "four hundred thirty-four billion, two hundred thirteen million, one hundred thirty thousand, three hundred one".
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