Base | Representation |
---|---|
bin | 101000011100000111… |
… | …001100011100101011 |
3 | 11011002002212122121012 |
4 | 220130013030130223 |
5 | 1202411324233003 |
6 | 31540353334135 |
7 | 3065010065414 |
oct | 503407143453 |
9 | 134062778535 |
10 | 43421321003 |
11 | 17462227165 |
12 | 84b986734b |
13 | 412cb31b68 |
14 | 215cb2880b |
15 | 11e20518d8 |
hex | a1c1cc72b |
43421321003 has 2 divisors, whose sum is σ = 43421321004. Its totient is φ = 43421321002.
The previous prime is 43421320997. The next prime is 43421321011. The reversal of 43421321003 is 30012312434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43421321003 - 212 = 43421316907 is a prime.
It is a super-2 number, since 2×434213210032 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 43421321003.
It is not a weakly prime, because it can be changed into another prime (43421321023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21710660501 + 21710660502.
It is an arithmetic number, because the mean of its divisors is an integer number (21710660502).
Almost surely, 243421321003 is an apocalyptic number.
43421321003 is a deficient number, since it is larger than the sum of its proper divisors (1).
43421321003 is an equidigital number, since it uses as much as digits as its factorization.
43421321003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 43421321003 its reverse (30012312434), we get a palindrome (73433633437).
The spelling of 43421321003 in words is "forty-three billion, four hundred twenty-one million, three hundred twenty-one thousand, three".
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