Base | Representation |
---|---|
bin | 110001010111010100010110… |
… | …0000101011011101000110001 |
3 | 2002221102101112110201202122021 |
4 | 1202232220230011123220301 |
5 | 423403122411341444213 |
6 | 4135254504531511441 |
7 | 160313610300511336 |
oct | 14256505405335061 |
9 | 2087371473652567 |
10 | 434213343312433 |
11 | 116398932421653 |
12 | 40849556158581 |
13 | 158391b132a829 |
14 | 79320761ca98d |
15 | 352ed439a0d8d |
hex | 18aea2c15ba31 |
434213343312433 has 2 divisors, whose sum is σ = 434213343312434. Its totient is φ = 434213343312432.
The previous prime is 434213343312391. The next prime is 434213343312461. The reversal of 434213343312433 is 334213343312434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 228501074527504 + 205712268784929 = 15116252^2 + 14342673^2 .
It is a cyclic number.
It is not a de Polignac number, because 434213343312433 - 29 = 434213343311921 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 434213343312433.
It is not a weakly prime, because it can be changed into another prime (434213343312233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217106671656216 + 217106671656217.
It is an arithmetic number, because the mean of its divisors is an integer number (217106671656217).
Almost surely, 2434213343312433 is an apocalyptic number.
It is an amenable number.
434213343312433 is a deficient number, since it is larger than the sum of its proper divisors (1).
434213343312433 is an equidigital number, since it uses as much as digits as its factorization.
434213343312433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2239488, while the sum is 43.
Adding to 434213343312433 its reverse (334213343312434), we get a palindrome (768426686624867).
Subtracting from 434213343312433 its reverse (334213343312434), we obtain a palindrome (99999999999999).
The spelling of 434213343312433 in words is "four hundred thirty-four trillion, two hundred thirteen billion, three hundred forty-three million, three hundred twelve thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •