Base | Representation |
---|---|
bin | 10011101111110000001011… |
… | …00010101011111011110001 |
3 | 12200202010022122012111222211 |
4 | 21313320011202223323301 |
5 | 21142412142324411424 |
6 | 232203520003332121 |
7 | 12101102621015662 |
oct | 1167700542537361 |
9 | 180663278174884 |
10 | 43422212341489 |
11 | 12921290941063 |
12 | 4a53623081041 |
13 | 1b2c90a573517 |
14 | aa19095cb369 |
15 | 5047a0e2db94 |
hex | 277e058abef1 |
43422212341489 has 2 divisors, whose sum is σ = 43422212341490. Its totient is φ = 43422212341488.
The previous prime is 43422212341451. The next prime is 43422212341493. The reversal of 43422212341489 is 98414321222434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29982414384400 + 13439797957089 = 5475620^2 + 3666033^2 .
It is a cyclic number.
It is not a de Polignac number, because 43422212341489 - 245 = 8237840252657 is a prime.
It is not a weakly prime, because it can be changed into another prime (43422212347489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21711106170744 + 21711106170745.
It is an arithmetic number, because the mean of its divisors is an integer number (21711106170745).
Almost surely, 243422212341489 is an apocalyptic number.
It is an amenable number.
43422212341489 is a deficient number, since it is larger than the sum of its proper divisors (1).
43422212341489 is an equidigital number, since it uses as much as digits as its factorization.
43422212341489 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2654208, while the sum is 49.
The spelling of 43422212341489 in words is "forty-three trillion, four hundred twenty-two billion, two hundred twelve million, three hundred forty-one thousand, four hundred eighty-nine".
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