Base | Representation |
---|---|
bin | 10011101111110000001011… |
… | …00010101011111101100001 |
3 | 12200202010022122012112010222 |
4 | 21313320011202223331201 |
5 | 21142412142324412401 |
6 | 232203520003332425 |
7 | 12101102621016212 |
oct | 1167700542537541 |
9 | 180663278175128 |
10 | 43422212341601 |
11 | 12921290941155 |
12 | 4a53623081115 |
13 | 1b2c90a5735a2 |
14 | aa19095cb409 |
15 | 5047a0e2dc1b |
hex | 277e058abf61 |
43422212341601 has 2 divisors, whose sum is σ = 43422212341602. Its totient is φ = 43422212341600.
The previous prime is 43422212341577. The next prime is 43422212341691. The reversal of 43422212341601 is 10614321222434.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43419876069376 + 2336272225 = 6589376^2 + 48335^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43422212341601 is a prime.
It is not a weakly prime, because it can be changed into another prime (43422212341691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21711106170800 + 21711106170801.
It is an arithmetic number, because the mean of its divisors is an integer number (21711106170801).
Almost surely, 243422212341601 is an apocalyptic number.
It is an amenable number.
43422212341601 is a deficient number, since it is larger than the sum of its proper divisors (1).
43422212341601 is an equidigital number, since it uses as much as digits as its factorization.
43422212341601 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
The spelling of 43422212341601 in words is "forty-three trillion, four hundred twenty-two billion, two hundred twelve million, three hundred forty-one thousand, six hundred one".
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