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43423632433 is a prime number
BaseRepresentation
bin101000011100010000…
…000000110000110001
311011002021020002021201
4220130100000300301
51202412422214213
631540515051201
73065035533316
oct503420006061
9134067202251
1043423632433
1117463565835
1284ba5a0b01
134130460c7c
14215d16ad0d
1511e235b6dd
hexa1c400c31

43423632433 has 2 divisors, whose sum is σ = 43423632434. Its totient is φ = 43423632432.

The previous prime is 43423632383. The next prime is 43423632449. The reversal of 43423632433 is 33423632434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33963541264 + 9460091169 = 184292^2 + 97263^2 .

It is a cyclic number.

It is not a de Polignac number, because 43423632433 - 213 = 43423624241 is a prime.

It is a super-2 number, since 2×434236324332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43423632392 and 43423632401.

It is not a weakly prime, because it can be changed into another prime (43423630433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21711816216 + 21711816217.

It is an arithmetic number, because the mean of its divisors is an integer number (21711816217).

Almost surely, 243423632433 is an apocalyptic number.

It is an amenable number.

43423632433 is a deficient number, since it is larger than the sum of its proper divisors (1).

43423632433 is an equidigital number, since it uses as much as digits as its factorization.

43423632433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 373248, while the sum is 37.

Subtracting from 43423632433 its reverse (33423632434), we obtain a palindrome (9999999999).

The spelling of 43423632433 in words is "forty-three billion, four hundred twenty-three million, six hundred thirty-two thousand, four hundred thirty-three".