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43425343243201 is a prime number
BaseRepresentation
bin10011101111110110000000…
…01010001000001111000001
312200202102101211112210201111
421313323000022020033001
521142440100332240301
6232205154405403321
712101243326156213
oct1167730012101701
9180672354483644
1043425343243201
1112922648189937
124a54157709541
131b2ccb90caa9a
14aa1b2534a5b3
155048d5c2d551
hex277ec02883c1

43425343243201 has 2 divisors, whose sum is σ = 43425343243202. Its totient is φ = 43425343243200.

The previous prime is 43425343243187. The next prime is 43425343243207. The reversal of 43425343243201 is 10234234352434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29807767203201 + 13617576040000 = 5459649^2 + 3690200^2 .

It is a cyclic number.

It is not a de Polignac number, because 43425343243201 - 211 = 43425343241153 is a prime.

It is not a weakly prime, because it can be changed into another prime (43425343243207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21712671621600 + 21712671621601.

It is an arithmetic number, because the mean of its divisors is an integer number (21712671621601).

Almost surely, 243425343243201 is an apocalyptic number.

It is an amenable number.

43425343243201 is a deficient number, since it is larger than the sum of its proper divisors (1).

43425343243201 is an equidigital number, since it uses as much as digits as its factorization.

43425343243201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 829440, while the sum is 40.

Adding to 43425343243201 its reverse (10234234352434), we get a palindrome (53659577595635).

The spelling of 43425343243201 in words is "forty-three trillion, four hundred twenty-five billion, three hundred forty-three million, two hundred forty-three thousand, two hundred one".