Base | Representation |
---|---|
bin | 1100101000111100101… |
… | …11010111110010010001 |
3 | 1112112000012012211101121 |
4 | 12110132113113302101 |
5 | 24103422042440423 |
6 | 531303140402241 |
7 | 43243246531651 |
oct | 6243627276221 |
9 | 1475005184347 |
10 | 434301140113 |
11 | 158205742685 |
12 | 702066a6381 |
13 | 31c53b31859 |
14 | 1703d950361 |
15 | b46ce2e45d |
hex | 651e5d7c91 |
434301140113 has 8 divisors (see below), whose sum is σ = 460097269632. Its totient is φ = 408532677696.
The previous prime is 434301140111. The next prime is 434301140129. The reversal of 434301140113 is 311041103434.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 434301140113 - 21 = 434301140111 is a prime.
It is a super-3 number, since 3×4343011401133 (a number of 36 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (434301140111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6884445 + ... + 6947242.
It is an arithmetic number, because the mean of its divisors is an integer number (57512158704).
Almost surely, 2434301140113 is an apocalyptic number.
It is an amenable number.
434301140113 is a deficient number, since it is larger than the sum of its proper divisors (25796129519).
434301140113 is a wasteful number, since it uses less digits than its factorization.
434301140113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13833551.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 434301140113 its reverse (311041103434), we get a palindrome (745342243547).
The spelling of 434301140113 in words is "four hundred thirty-four billion, three hundred one million, one hundred forty thousand, one hundred thirteen".
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