Base | Representation |
---|---|
bin | 101000011100110100… |
… | …100011010011111011 |
3 | 11011002221020201210022 |
4 | 220130310203103323 |
5 | 1202422400224011 |
6 | 31541500241055 |
7 | 3065213126462 |
oct | 503464432373 |
9 | 134087221708 |
10 | 43433211131 |
11 | 17468a08412 |
12 | 850184018b |
13 | 4132435b3b |
14 | 21605419d9 |
15 | 11e30ee8db |
hex | a1cd234fb |
43433211131 has 2 divisors, whose sum is σ = 43433211132. Its totient is φ = 43433211130.
The previous prime is 43433211121. The next prime is 43433211167. The reversal of 43433211131 is 13111233434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43433211131 - 26 = 43433211067 is a prime.
It is a super-2 number, since 2×434332111312 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 43433211131.
It is not a weakly prime, because it can be changed into another prime (43433211121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21716605565 + 21716605566.
It is an arithmetic number, because the mean of its divisors is an integer number (21716605566).
Almost surely, 243433211131 is an apocalyptic number.
43433211131 is a deficient number, since it is larger than the sum of its proper divisors (1).
43433211131 is an equidigital number, since it uses as much as digits as its factorization.
43433211131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 26.
Adding to 43433211131 its reverse (13111233434), we get a palindrome (56544444565).
The spelling of 43433211131 in words is "forty-three billion, four hundred thirty-three million, two hundred eleven thousand, one hundred thirty-one".
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