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434401113131 is a prime number
BaseRepresentation
bin1100101001001000101…
…00101111010000101011
31112112021011022222120222
412110210110233100223
524104123141110011
6531321111240255
743245602352326
oct6244424572053
91475234288528
10434401113131
11158257115907
127023407908b
1331c6b765c9b
141704cd357bd
15b476acaddb
hex652452f42b

434401113131 has 2 divisors, whose sum is σ = 434401113132. Its totient is φ = 434401113130.

The previous prime is 434401113121. The next prime is 434401113149. The reversal of 434401113131 is 131311104434.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-434401113131 is a prime.

It is a super-2 number, since 2×4344011131312 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 434401113131.

It is not a weakly prime, because it can be changed into another prime (434401113121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217200556565 + 217200556566.

It is an arithmetic number, because the mean of its divisors is an integer number (217200556566).

Almost surely, 2434401113131 is an apocalyptic number.

434401113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

434401113131 is an equidigital number, since it uses as much as digits as its factorization.

434401113131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 434401113131 its reverse (131311104434), we get a palindrome (565712217565).

The spelling of 434401113131 in words is "four hundred thirty-four billion, four hundred one million, one hundred thirteen thousand, one hundred thirty-one".