Base | Representation |
---|---|
bin | 1100101001001101100… |
… | …01001101011100101001 |
3 | 1112112101000111220212020 |
4 | 12110212301031130221 |
5 | 24104214141144431 |
6 | 531325134335053 |
7 | 43246611120546 |
oct | 6244661153451 |
9 | 1475330456766 |
10 | 434442131241 |
11 | 158278291378 |
12 | 7024595a489 |
13 | 31c770c8061 |
14 | 17054571bcd |
15 | b47a4ce696 |
hex | 6526c4d729 |
434442131241 has 8 divisors (see below), whose sum is σ = 583817247744. Its totient is φ = 287347551120.
The previous prime is 434442131237. The next prime is 434442131311. The reversal of 434442131241 is 142131244434.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 434442131241 - 22 = 434442131237 is a prime.
It is not an unprimeable number, because it can be changed into a prime (434442131741) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 570133650 + ... + 570134411.
It is an arithmetic number, because the mean of its divisors is an integer number (72977155968).
Almost surely, 2434442131241 is an apocalyptic number.
It is an amenable number.
434442131241 is a deficient number, since it is larger than the sum of its proper divisors (149375116503).
434442131241 is a wasteful number, since it uses less digits than its factorization.
434442131241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1140268191.
The product of its digits is 36864, while the sum is 33.
Adding to 434442131241 its reverse (142131244434), we get a palindrome (576573375675).
The spelling of 434442131241 in words is "four hundred thirty-four billion, four hundred forty-two million, one hundred thirty-one thousand, two hundred forty-one".
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