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434442131741 is a prime number
BaseRepresentation
bin1100101001001101100…
…01001101100100011101
31112112101000111221112202
412110212301031210131
524104214141203431
6531325134341245
743246611122162
oct6244661154435
91475330457482
10434442131741
11158278291792
127024595a825
1331c770c8357
1417054572069
15b47a4ce8cb
hex6526c4d91d

434442131741 has 2 divisors, whose sum is σ = 434442131742. Its totient is φ = 434442131740.

The previous prime is 434442131731. The next prime is 434442131803. The reversal of 434442131741 is 147131244434.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 225771323716 + 208670808025 = 475154^2 + 456805^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-434442131741 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 434442131695 and 434442131704.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (434442131701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217221065870 + 217221065871.

It is an arithmetic number, because the mean of its divisors is an integer number (217221065871).

Almost surely, 2434442131741 is an apocalyptic number.

It is an amenable number.

434442131741 is a deficient number, since it is larger than the sum of its proper divisors (1).

434442131741 is an equidigital number, since it uses as much as digits as its factorization.

434442131741 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 129024, while the sum is 38.

The spelling of 434442131741 in words is "four hundred thirty-four billion, four hundred forty-two million, one hundred thirty-one thousand, seven hundred forty-one".