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4350114150793 is a prime number
BaseRepresentation
bin111111010011010111000…
…000100011100110001001
3120101212101221020100202021
4333103113000203212021
51032233013210311133
613130225335204441
7626166612121405
oct77232700434611
916355357210667
104350114150793
111427967038114
125a30b8516721
132572a22237b8
14110792008105
157825305b52d
hex3f4d7023989

4350114150793 has 2 divisors, whose sum is σ = 4350114150794. Its totient is φ = 4350114150792.

The previous prime is 4350114150731. The next prime is 4350114150829. The reversal of 4350114150793 is 3970514110534.

4350114150793 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2811430199824 + 1538683950969 = 1676732^2 + 1240437^2 .

It is a cyclic number.

It is not a de Polignac number, because 4350114150793 - 221 = 4350112053641 is a prime.

It is not a weakly prime, because it can be changed into another prime (4350114151793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175057075396 + 2175057075397.

It is an arithmetic number, because the mean of its divisors is an integer number (2175057075397).

Almost surely, 24350114150793 is an apocalyptic number.

It is an amenable number.

4350114150793 is a deficient number, since it is larger than the sum of its proper divisors (1).

4350114150793 is an equidigital number, since it uses as much as digits as its factorization.

4350114150793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 226800, while the sum is 43.

The spelling of 4350114150793 in words is "four trillion, three hundred fifty billion, one hundred fourteen million, one hundred fifty thousand, seven hundred ninety-three".