Base | Representation |
---|---|
bin | 111111010011100100011… |
… | …110001011001100110001 |
3 | 120101212222200020122200011 |
4 | 333103210132023030301 |
5 | 1032233444021101433 |
6 | 13130304004254521 |
7 | 626205324015313 |
oct | 77234436131461 |
9 | 16355880218604 |
10 | 4350340018993 |
11 | 1427a72589251 |
12 | 5a31600a1441 |
13 | 257309c67217 |
14 | 1107b40017b3 |
15 | 78267cc53cd |
hex | 3f4e478b331 |
4350340018993 has 2 divisors, whose sum is σ = 4350340018994. Its totient is φ = 4350340018992.
The previous prime is 4350340018931. The next prime is 4350340019009. The reversal of 4350340018993 is 3998100430534.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3104196468129 + 1246143550864 = 1761873^2 + 1116308^2 .
It is a cyclic number.
It is not a de Polignac number, because 4350340018993 - 237 = 4212901065521 is a prime.
It is not a weakly prime, because it can be changed into another prime (4350340018903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175170009496 + 2175170009497.
It is an arithmetic number, because the mean of its divisors is an integer number (2175170009497).
Almost surely, 24350340018993 is an apocalyptic number.
It is an amenable number.
4350340018993 is a deficient number, since it is larger than the sum of its proper divisors (1).
4350340018993 is an equidigital number, since it uses as much as digits as its factorization.
4350340018993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1399680, while the sum is 49.
The spelling of 4350340018993 in words is "four trillion, three hundred fifty billion, three hundred forty million, eighteen thousand, nine hundred ninety-three".
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