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4350996918353 is a prime number
BaseRepresentation
bin111111010100001011101…
…000000011000001010001
3120101221200110022121012002
4333110023220003001101
51032241320202341403
613130453112043345
7626230521405641
oct77241350030121
916357613277162
104350996918353
11142827a36a488
125a3304093555
132573b3095677
1411083735a521
15782a57d2188
hex3f50ba03051

4350996918353 has 2 divisors, whose sum is σ = 4350996918354. Its totient is φ = 4350996918352.

The previous prime is 4350996918341. The next prime is 4350996918407. The reversal of 4350996918353 is 3538196990534.

4350996918353 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2324109397009 + 2026887521344 = 1524503^2 + 1423688^2 .

It is a cyclic number.

It is not a de Polignac number, because 4350996918353 - 228 = 4350728482897 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4350996918353.

It is not a weakly prime, because it can be changed into another prime (4350996918253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175498459176 + 2175498459177.

It is an arithmetic number, because the mean of its divisors is an integer number (2175498459177).

Almost surely, 24350996918353 is an apocalyptic number.

It is an amenable number.

4350996918353 is a deficient number, since it is larger than the sum of its proper divisors (1).

4350996918353 is an equidigital number, since it uses as much as digits as its factorization.

4350996918353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 94478400, while the sum is 65.

The spelling of 4350996918353 in words is "four trillion, three hundred fifty billion, nine hundred ninety-six million, nine hundred eighteen thousand, three hundred fifty-three".