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4351114514057 is a prime number
BaseRepresentation
bin111111010100010010101…
…000101000111010001001
3120101221222122121002011112
4333110102220220322021
51032242040303422212
613130512512340105
7626233450064363
oct77242250507211
916357878532145
104351114514057
11142832a789913
125a3337544635
1325740155a11c
14110848c0bd33
15782b0cb0422
hex3f512a28e89

4351114514057 has 2 divisors, whose sum is σ = 4351114514058. Its totient is φ = 4351114514056.

The previous prime is 4351114514009. The next prime is 4351114514063. The reversal of 4351114514057 is 7504154111534.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3620301538681 + 730812975376 = 1902709^2 + 854876^2 .

It is a cyclic number.

It is not a de Polignac number, because 4351114514057 - 212 = 4351114509961 is a prime.

It is not a weakly prime, because it can be changed into another prime (4351114514077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175557257028 + 2175557257029.

It is an arithmetic number, because the mean of its divisors is an integer number (2175557257029).

Almost surely, 24351114514057 is an apocalyptic number.

It is an amenable number.

4351114514057 is a deficient number, since it is larger than the sum of its proper divisors (1).

4351114514057 is an equidigital number, since it uses as much as digits as its factorization.

4351114514057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168000, while the sum is 41.

The spelling of 4351114514057 in words is "four trillion, three hundred fifty-one billion, one hundred fourteen million, five hundred fourteen thousand, fifty-seven".